(1-x^2)/2=(x^2-1)/3

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Solution for (1-x^2)/2=(x^2-1)/3 equation: 


x in (-oo:+oo)

(1-x^2)/2 = (x^2-1)/3 // - (x^2-1)/3

(1-x^2)/2-((x^2-1)/3) = 0

(1-x^2)/2+(-1*(x^2-1))/3 = 0

(3*(1-x^2))/(2*3)+(-1*2*(x^2-1))/(2*3) = 0

3*(1-x^2)-1*2*(x^2-1) = 0

5-5*x^2 = 0

(5-5*x^2)/(2*3) = 0

(5-5*x^2)/(2*3) = 0 // * 2*3

5-5*x^2 = 0

-5*x^2 = -5 // : -5

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in { 1, -1 }

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